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Proof step 4 from proof fill-fill-01 (previous step)

¬ n ≤ # fillsgn(n, bits) ⊦ bits = [], fillsgn(n, fillsgn(n, bits)) = fillsgn(n, bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
# fillsgn(n, bits) < n ⊦ fillsgn(n, fillsgn(n, bits)) = fillsgn(n, bits), bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0;% ⊦ m < n → n ≠ 0; (forward)% ⊦ ¬ m ≤ n ↔ n < m;