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Proof step 2 from proof fill-last (previous step)

⊦ bits = [], n = 0, fillsgn(n, bits + boolvar ') = fillsgn(n - 1, bits) + boolvar '

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
n = m + 1 ⊦ bits = [], n = 0, fillsgn(n, bits + boolvar ') = fillsgn(m, bits) + boolvar '

Rule argument

seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [n, m] rotate: T spec: nat inst: name: elim-pred-c

Additional information

Used simplifier rules: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: n, m