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Proof step 3 from proof fill-last (previous step)

n = m + 1 ⊦ bits = [], n = 0, fillsgn(n, bits + boolvar ') = fillsgn(m, bits) + boolvar '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ bits = [], fillsgn(m + 1, bits + boolvar ') = fillsgn(m, bits) + boolvar '

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + 1 ≠ 0;