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Proof step 14 from proof fill-lastn-03 (previous step)

# bits ≤ m ∧ bits ≠ [], m ≤ n ⊦ bits = [], lastn(m, fillsgn(n, bits)) = lastn(m, mklist(bits.first, m - # bits) + bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
# bits ≤ m, m ≤ n, # bits ≤ n ⊦ lastn(m, fillsgn(n, bits)) = lastn(m, mklist(bits.first, m - # bits) + bits), bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ n ≤ n0 ∧ n0 ≤ n1 → n ≤ n1; (forward)