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Proof step 2 from proof fill-lastn-03 (previous step)

m ≤ n ⊦ bits = [], lastn(m, fillsgn(n, bits)) = lastn(m, fillsgn(m, bits))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ # bits ≤ n ∧ bits ≠ [] → fillsgn(n, bits) = mklist(bits.first, n - # bits) + bits
Proof step 4:
¬(# bits ≤ m ∧ bits ≠ []), m ≤ n ⊦ bits = [], lastn(m, fillsgn(n, bits)) = lastn(m, fillsgn(m, bits))
Proof step 14:
# bits ≤ m ∧ bits ≠ [], m ≤ n ⊦ bits = [], lastn(m, fillsgn(n, bits)) = lastn(m, mklist(bits.first, m - # bits) + bits)

Rule argument

name: fill-fill rotate: F subst: [bits, n] → [bits, m]

Additional information

Used terms: bits, m