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Proof step 5 from proof lastn-fill-sgn (previous step)

n < # bits ⊦ lastn(n, fillsgn(n, sgn(bits))) = lastn(n, bits), bits = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ n = # bits → fillsgn(n, sgn(bits)) = bits
Proof step 7:
n ≠ # bits, n < # bits ⊦ lastn(n, fillsgn(n, sgn(bits))) = lastn(n, bits), bits = []

Rule argument

name: fill-sgn rotate: F subst: [bits, n] → [bits, n]

Additional information

Used terms: bits, n