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Proof step 7 from proof lastn-fill-sgn (
previous step
)
n ≠ # bits, n < # bits ⊦ lastn(n, fillsgn(n, sgn(bits))) = lastn(n, bits), bits = []
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 8
:
n < # bits ⊦ n = # bits, bits = [], lastn(n, fillsgn(n, sgn(bits))) = lastn(n, bits)
Rule argument
Additional information