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Proof step 8 from proof lastn-fill-sgn (previous step)

n < # bits ⊦ n = # bits, bits = [], lastn(n, fillsgn(n, sgn(bits))) = lastn(n, bits)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ n ≤ # bits → fillsgn(n, bits) = bits
Proof step 10:
¬ n ≤ # sgn(bits), n < # bits ⊦ n = # bits, bits = [], lastn(n, fillsgn(n, sgn(bits))) = lastn(n, bits)

Rule argument

name: fillsgn-longer rotate: F subst: [bits, n] → [sgn(bits), n]

Additional information

Used simplifier rules: sgn-lastn-01: ⊦ n ≤ # sgn(bits) ∧ bits ≠ [] → lastn(n, sgn(bits)) = lastn(n, bits); Used terms: sgn(bits), n