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Proof step 14 from proof sgn-append-01 (previous step)

(false ∈ bits ∨ ¬ boolvar) ∧ (true ∈ bits ∨ boolvar) → (∀ bits0. sgn((boolvar ' + bits) + bits0) = sgn(boolvar ' + bits) + bits0) ⊦ sgn(boolvar ' + bits + bits1) = sgn(boolvar ' + bits) + bits1, boolvar ∧ ¬ false ∈ bits ∧ boolvar, ¬ boolvar ∧ ¬ true ∈ bits ∧ ¬ boolvar

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 1

Additional information