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Proof step 15 from proof sgn-append-01 (previous step)

⊦ (false ∈ bits ∨ ¬ boolvar) ∧ (true ∈ bits ∨ boolvar), sgn(boolvar ' + bits + bits1) = sgn(boolvar ' + bits) + bits1, boolvar ∧ ¬ false ∈ bits ∧ boolvar, ¬ boolvar ∧ ¬ true ∈ bits ∧ ¬ boolvar

User applied rule case distinction

And closed the goal!

Rule argument

pos: right 1

Proof step 15 from proof sgn-append-01 (previous step)

User applied rule case distinction

And closed the goal!

Rule argument

Additional information