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Proof step 14 from proof sgn-append-02 (previous step)

true ∈ bits ∨ boolvar → (∀ bits0. sgn((boolvar ' + bits) + false ' + bits0) = sgn(boolvar ' + bits) + false ' + bits0) ⊦ sgn(boolvar ' + bits + false ' + bits1) = sgn(boolvar ' + bits) + false ' + bits1, ¬ boolvar ∧ ¬ true ∈ bits ∧ ¬ boolvar

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 1

Additional information