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Proof step 15 from proof sgn-append-02 (previous step)

∀ bits0. sgn((boolvar ' + bits) + false ' + bits0) = sgn(boolvar ' + bits) + false ' + bits0 ⊦ sgn(boolvar ' + bits + false ' + bits1) = sgn(boolvar ' + bits) + false ' + bits1, ¬ boolvar ∧ ¬ true ∈ bits ∧ ¬ boolvar

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: bits1

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used terms: bits1