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Proof step 6 from proof sgn-append-06 (previous step)

true ∈ bits + boolvar ' ∧ false ∈ bits + boolvar ' → sgn((bits + boolvar ') + bits1) = sgn(bits + boolvar ') + bits1, (¬ boolvar) ∈ bits ⊦ sgn(bits + boolvar ' + bits1) = sgn(bits) + boolvar ' + bits1

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 1

Additional information