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Proof step 9 from proof sgn-append-06 (previous step)

sgn((bits + boolvar ') + bits1) = sgn(bits + boolvar ') + bits1, (¬ boolvar) ∈ bits ⊦ sgn(bits + boolvar ' + bits1) = sgn(bits) + boolvar ' + bits1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
sgn((bits + boolvar ') + bits1) = sgn(bits + boolvar ') + bits1, (¬ boolvar) ∈ bits ⊦ sgn(bits + boolvar ') = sgn(bits) + boolvar '

Rule argument

Additional information

Used simplifier rules: ⊦ bits + bits0 = bits1 + bits0 ↔ bits = bits1;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;