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Proof step 5 from proof sgn-append (previous step)

¬ boolvar0, ∀ boolvar, bits1. sgn(boolvar ' + bits0 + bits1) = sgn(boolvar ' + bits1) ∨ (¬ boolvar) ∈ bits0 ⊦ boolvar, sgn(boolvar0 ' + (boolvar ' + bits0) + bits1) = sgn(boolvar0 ' + bits1), (¬ boolvar0) ∈ bits0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: sgn-rec: ⊦ sgn(boolvar ' + boolvar ' + bits) = sgn(boolvar ' + bits);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;