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Proof step 6 from proof sgn-append (previous step)

∀ boolvar, bits1. sgn(boolvar ' + bits0 + bits1) = sgn(boolvar ' + bits1) ∨ (¬ boolvar) ∈ bits0 ⊦ sgn(false ' + bits0 + bits1) = sgn(false ' + bits1), true ∈ bits0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: false, bits1

Additional information

Used terms: false, bits1