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Proof step 6 from proof sgn-base-04 (previous step)

bits = boolvar0 + bits0 ⊦ sgn(boolvar ' + bits) = boolvar ' + bits, boolvar0 ↔ ¬ boolvar, bits = [], boolvar ∈ bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
⊦ boolvar0 ↔ ¬ boolvar, sgn(boolvar ' + boolvar0 ' + bits0) = boolvar ' + boolvar0 ' + bits0, boolvar ↔ boolvar0, boolvar ∈ bits0

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ boolvar ∈ boolvar0 ' + bits ↔ ¬(boolvar ↔ boolvar0) ∧ ¬ boolvar ∈ bits;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];% ⊦ boolvar + bits = boolvar ' + bits;