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Proof step 7 from proof sgn-base-04 (previous step)

⊦ boolvar0 ↔ ¬ boolvar, sgn(boolvar ' + boolvar0 ' + bits0) = boolvar ' + boolvar0 ' + bits0, boolvar ↔ boolvar0, boolvar ∈ bits0

User applied rule case distinction

And closed the goal!

Rule argument

pos: right 1

Additional information

Used simplifier rules: sgn-rec: ⊦ sgn(boolvar ' + boolvar ' + bits) = sgn(boolvar ' + bits);%sgn-rec: ⊦ sgn(boolvar ' + boolvar ' + bits) = sgn(boolvar ' + bits);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;