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Proof step 37 from proof sgn-last-04 (previous step)

¬ boolvar1, ∀ boolvar. (¬ boolvar ↔ boolvar1) ∨ (¬ boolvar) ∈ bits1 → sgn((boolvar1 ' + bits1) + boolvar ') = sgn(boolvar1 ' + bits1) + boolvar ' ⊦ boolvar1, sgn(boolvar1 ' + bits1 + boolvar0 ') = sgn(boolvar1 ' + bits1) + boolvar0 ', ¬(¬ boolvar0 ↔ boolvar1) ∧ ¬ (¬ boolvar0) ∈ bits1 ∧ ¬(¬ boolvar0 ↔ boolvar1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 38:
∀ boolvar. boolvar ∨ true ∈ bits1 → sgn((false ' + bits1) + boolvar ') = sgn(false ' + bits1) + boolvar ' ⊦ sgn(false ' + bits1 + boolvar0 ') = sgn(false ' + bits1) + boolvar0 ', ¬ boolvar0 ∧ ¬ boolvar0 ∧ ¬ (¬ boolvar0) ∈ bits1

Proof step 37 from proof sgn-last-04 (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information