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Proof step 38 from proof sgn-last-04 (previous step)

∀ boolvar. boolvar ∨ true ∈ bits1 → sgn((false ' + bits1) + boolvar ') = sgn(false ' + bits1) + boolvar ' ⊦ sgn(false ' + bits1 + boolvar0 ') = sgn(false ' + bits1) + boolvar0 ', ¬ boolvar0 ∧ ¬ boolvar0 ∧ ¬ (¬ boolvar0) ∈ bits1

User applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: boolvar0 abort: F discard: F computed: T

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used terms: boolvar0