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Proof step 19 from proof sgn-lastn-01 (previous step)

n < #(boolvar ' + boolvar ' + bits), n ≤ # sgn(boolvar ' + bits), ∀ n0. ¬ # sgn(boolvar ' + bits) < n0 → lastn(n0, sgn(boolvar ' + bits)) = lastn(n0, boolvar ' + bits) ⊦ lastn(n, sgn(boolvar ' + bits)) = lastn(n, (boolvar ' + boolvar ' + bits).rest)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;%n < n0 ⊦ (* n) ≠ m0 + (* n0);% ⊦ m < n → n ≠ 0; (forward)% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ (boolvar ' + bits).rest = bits;