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Proof step 20 from proof sgn-lastn-01 (previous step)

n < 2 + # bits, n ≤ # sgn(boolvar ' + bits), ∀ n0. ¬ # sgn(boolvar ' + bits) < n0 → lastn(n0, sgn(boolvar ' + bits)) = lastn(n0, boolvar ' + bits) ⊦ lastn(n, sgn(boolvar ' + bits)) = lastn(n, boolvar ' + bits)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: n

Additional information

Used simplifier rules: ⊦ m ≤ n → (n < m ↔ false); Used terms: n