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Proof step 2 from proof sgn-lastn (previous step)

⊦ lastn(# bits0 + 1, sgn(bits + boolvar ') + bits0) = boolvar ' + bits0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ (¬ boolvar) ∈ bits → sgn(bits + boolvar ') = sgn(bits) + boolvar '
Proof step 4:
¬ (¬ boolvar) ∈ bits ⊦ lastn(# bits0 + 1, sgn(bits + boolvar ') + bits0) = boolvar ' + bits0
Proof step 10:
(¬ boolvar) ∈ bits ⊦ lastn(# bits0 + 1, (sgn(bits) + boolvar ') + bits0) = boolvar ' + bits0

Rule argument

name: sgn-last-04 rotate: F subst: [boolvar, bits] → [boolvar, bits]

Additional information

Used terms: boolvar, bits