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Proof step 4 from proof sgn-lastn (
previous step
)
¬ (¬ boolvar) ∈ bits ⊦ lastn(# bits0 + 1, sgn(bits + boolvar ') + bits0) = boolvar ' + bits0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 5
:
⊦ lastn(# bits0 + 1, sgn(bits + boolvar ') + bits0) = boolvar ' + bits0, (¬ boolvar) ∈ bits
Rule argument
Additional information