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Proof step 2 from proof sgn-one-01 (previous step)

⊦ bits = [], sgn(bits) = boolvar ' ↔ ¬ (¬ boolvar) ∈ bits

User applied rule cut formula

And obtained the following new goals

Proof step 3:
boolvar ⊦ bits = [], sgn(bits) = boolvar ' ↔ ¬ (¬ boolvar) ∈ bits
Proof step 17:
⊦ boolvar, bits = [], sgn(bits) = boolvar ' ↔ ¬ (¬ boolvar) ∈ bits

Rule argument

fma: boolvar

Additional information

Used formulas: boolvar