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Proof step 3 from proof sgn-one-01 (previous step)

boolvar ⊦ bits = [], sgn(bits) = boolvar ' ↔ ¬ (¬ boolvar) ∈ bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
sgn(bits) = true ', false ∈ bits ⊦ bits = []

Rule argument

Additional information

Used simplifier rules: sgn-true: ⊦ ¬ false ∈ bits ∧ bits ≠ [] → sgn(bits) = true ';% ⊦ boolvar ' = boolvar0 ' ↔ boolvar ↔ boolvar0;