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Proof step 24 from proof sgn-one-01 (previous step)

sgn(boolvar ' + bits0) = false ', sgn(bits0) = false ' ∧ true ∈ bits0 → bits0 = [] ⊦ bits0.first ↔ boolvar, ¬ true ∈ bits0 ∧ ¬ boolvar

User applied rule case distinction

And obtained the following new goals

Proof step 25:
bits0.first, sgn(boolvar ' + bits0) = false ', sgn(bits0) = false ' ∧ true ∈ bits0 → bits0 = [] ⊦ boolvar, ¬ true ∈ bits0 ∧ ¬ boolvar
Proof step 27:
boolvar, sgn(boolvar ' + bits0) = false ', sgn(bits0) = false ' ∧ true ∈ bits0 → bits0 = [] ⊦ bits0.first, ¬ true ∈ bits0 ∧ ¬ boolvar

Rule argument

pos: right 1

Additional information