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Proof step 27 from proof sgn-one-01 (previous step)

boolvar, sgn(boolvar ' + bits0) = false ', sgn(bits0) = false ' ∧ true ∈ bits0 → bits0 = [] ⊦ bits0.first, ¬ true ∈ bits0 ∧ ¬ boolvar

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 28:
sgn(true ' + bits0) = false ', true ∈ bits0 ⊦ bits0 = [], sgn(bits0) = false ', bits0.first

Rule argument

Additional information

Used simplifier rules: sgn-one: ⊦ sgn(boolvar ') = boolvar ';%sgn-base-04: ⊦ ¬ boolvar ∈ bits → sgn(boolvar ' + bits) = boolvar ' + bits;% ⊦ boolvar ' = boolvar0 ' + bits ↔ (boolvar ↔ boolvar0) ∧ bits = [];% ⊦ boolvar ' = boolvar0 ' ↔ boolvar ↔ boolvar0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + [] = bits;