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Proof step 2 from proof succ-fill (previous step)

false ∈ bits.rest ⊦ bits = [], fillsgn(n, bits) +1 = fillsgn(n, bits +1)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
bits = boolvar + bits0, false ∈ bits0 ⊦ bits = [], fillsgn(n, bits) +1 = fillsgn(n, bits +1)

Rule argument

seq: bits ≠ [] ⊦ (boolvar ↔ bits.first) ∧ bits0 = bits.rest ↔ bits = boolvar + bits0 subst: [bits, boolvar, bits0] → [bits, boolvar, bits0] rotate: T spec: list-data inst: bitlista name: elim-list-c

Additional information

Used simplifier rules: bits ≠ [] ⊦ (boolvar ↔ bits.first) ∧ bits0 = bits.rest ↔ bits = boolvar + bits0; (elim) Used terms: bits, boolvar, bits0