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Proof step 3 from proof succ-fill (previous step)

bits = boolvar + bits0, false ∈ bits0 ⊦ bits = [], fillsgn(n, bits) +1 = fillsgn(n, bits +1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
false ∈ bits0 ⊦ fillsgn(n, boolvar ' + bits0) +1 = fillsgn(n, boolvar ' + bits0 +1)

Rule argument

Additional information

Used simplifier rules: succ-zero-01: ⊦ false ∈ bits0 → (bits + bits0)+1 = bits + bits0 +1;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];% ⊦ boolvar + bits = boolvar ' + bits;