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Proof step 4 from proof succ-fill (previous step)

false ∈ bits0 ⊦ fillsgn(n, boolvar ' + bits0) +1 = fillsgn(n, boolvar ' + bits0 +1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ n ≤ # bits → fillsgn(n, bits) = bits
Proof step 6:
¬ n ≤ #(boolvar ' + bits0), false ∈ bits0 ⊦ fillsgn(n, boolvar ' + bits0) +1 = fillsgn(n, boolvar ' + bits0 +1)
Proof step 14:
n ≤ #(boolvar ' + bits0), false ∈ bits0 ⊦ (boolvar ' + bits0)+1 = fillsgn(n, boolvar ' + bits0 +1)

Rule argument

name: fillsgn-longer rotate: F subst: [bits, n] → [boolvar ' + bits0, n]

Additional information

Used terms: boolvar ' + bits0, n