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Proof step 15 from proof bib-ls-same-01 (previous step)

⊦ i < 0, b2i(i2b(i)) < i ↔ ¬ i < 128

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
0 ≤ i ⊦ b2i(i2b(i)) < i ↔ ¬ i < 128

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ ¬ i < j ↔ j ≤ i;