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Proof step 16 from proof bib-ls-same-01 (previous step)

0 ≤ i ⊦ b2i(i2b(i)) < i ↔ ¬ i < 128

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 17:
⊦ 0 ≤ i ∧ 127 < i % 256 → b2i(i2b(i)) = i % 256 - 256
Proof step 18:
¬(0 ≤ i ∧ 127 < i % 256), 0 ≤ i ⊦ b2i(i2b(i)) < i ↔ ¬ i < 128
Proof step 21:
0 ≤ i ∧ 127 < i % 256, 0 ≤ i ⊦ i % 256 - 256 < i ↔ ¬ i < 128

Rule argument

name: bib-pos-high rotate: F subst: [i] → [i]

Additional information

Used terms: i