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Proof step 21 from proof bib-ls-same-01 (previous step)

0 ≤ i ∧ 127 < i % 256, 0 ≤ i ⊦ i % 256 - 256 < i ↔ ¬ i < 128

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
0 < i % 256, 0 ≤ i, 127 < i % 256 ⊦ i % 256 < 256 + i ↔ ¬ i < 128

Rule argument

Additional information

Used simplifier rules: i0 ≠ 0, i0 < i ⊦ (* i) < j → (* i0) < j;% ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ i - j < i0 ↔ i < j + i0;