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Proof step 14 from proof bib-neg-high (previous step)

i = i0 * 256 + j0 ∧ j0 ≤ 0 ∧ abs(j0) < 256 ∧ i0 ≤ 0 ∧ 0 < 256, i ≤ ~256, ~128 ≤ j0, i < 0 ⊦ b2i(i2b(bits2int(lastn(8, int2bits(i))))) = j0, ~256 ≠ i ∧ lastn(8, int2bits(i)).first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
i0 * 256 + j0 < 0, i0 ≤ 0, j0 ≤ 0, ~128 ≤ j0, i0 * 256 + j0 ≤ ~256, abs(j0) < 256 ⊦ b2i(i2b(bits2int(lastn(8, int2bits(i0 * 256 + j0))))) = j0, ~256 ≠ i0 * 256 + j0 ∧ lastn(8, int2bits(i0 * 256 + j0)).first

Rule argument

Additional information

Used simplifier rules: zero-gels-03: ⊦ i < 0 ∧ 0 ≤ j → i ≤ j; from specification int-abs%forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs%forward-lele: ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward) from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2