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Proof step 15 from proof bib-neg-high (previous step)

i0 * 256 + j0 < 0, i0 ≤ 0, j0 ≤ 0, ~128 ≤ j0, i0 * 256 + j0 ≤ ~256, abs(j0) < 256 ⊦ b2i(i2b(bits2int(lastn(8, int2bits(i0 * 256 + j0))))) = j0, ~256 ≠ i0 * 256 + j0 ∧ lastn(8, int2bits(i0 * 256 + j0)).first

User applied rule cut formula

And obtained the following new goals

Proof step 16:
256 = 2 ^ 8, i0 * 256 + j0 < 0, i0 ≤ 0, j0 ≤ 0, ~128 ≤ j0, i0 * 256 + j0 ≤ ~256, abs(j0) < 256 ⊦ b2i(i2b(bits2int(lastn(8, int2bits(i0 * 256 + j0))))) = j0, ~256 ≠ i0 * 256 + j0 ∧ lastn(8, int2bits(i0 * 256 + j0)).first

Rule argument

fma: 256 = 2 ^ 8

Additional information

Used formulas: 256 = 2 ^ 8