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Proof step 1 from proof bib-neg-low (conclusion)

⊦ i < 0 ∧ i % 256 < ~128 → b2i(i2b(i)) = i % 256 + 256

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i % 256 < ~128, i < 0, i % 256 < 0 ⊦ b2i(i2b(i)) = i % 256 + 256

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)