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Proof step 2 from proof bib-neg-low (previous step)

i % 256 < ~128, i < 0, i % 256 < 0 ⊦ b2i(i2b(i)) = i % 256 + 256

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
~128 ≤ i, i ≤ 127 ⊦ b2i(i2b((* i))) = i
Proof step 4:
¬(~128 ≤ i ∧ i ≤ 127), i % 256 < ~128, i < 0, i % 256 < 0 ⊦ b2i(i2b(i)) = i % 256 + 256
Proof step 59:
~128 ≤ i ∧ i ≤ 127, i % 256 < ~128, i < 0, i % 256 < 0 ⊦ i = i % 256 + 256

Rule argument

name: num-ibbi rotate: F subst: [i] → [i]

Additional information

Used terms: i