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Proof step 4 from proof bib-neg-low (previous step)

¬(~128 ≤ i ∧ i ≤ 127), i % 256 < ~128, i < 0, i % 256 < 0 ⊦ b2i(i2b(i)) = i % 256 + 256

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
i % 256 < ~128, i < 0, i % 256 < 0, i < ~128 ⊦ b2i(i2b(i)) = i % 256 + 256

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i;% ⊦ ¬ i ≤ j ↔ j < i;