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Proof step 22 from proof bib-neg-low (previous step)

0 ≤ 7 ∧ ~(2 ^ (7 + 1)) ≤ j ∧ j < ~(2 ^ 7), j < ~1, i→n(7 + 2) = 9, j < 0, ~256 < j, j < ~128 ⊦ b2i(i2b(j + 2 ^ (n→i(i→n(7 + 2)) - 1))) = 256 + j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
j < ~1, j < 0, ~256 < j, ~256 ≤ j, j < ~128 ⊦ b2i(i2b(256 + j)) = 256 + j

Rule argument

Additional information

Used simplifier rules: ⊦ j ≤ i ∧ i < 0 → j < 0; (forward)%j0 ≠ 0, j ≤ j0 ⊦ i < (* j) → i < (* j0);