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Proof step 23 from proof bib-neg-low (previous step)

j < ~1, j < 0, ~256 < j, ~256 ≤ j, j < ~128 ⊦ b2i(i2b(256 + j)) = 256 + j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 24:
~128 ≤ i, i ≤ 127 ⊦ b2i(i2b((* i))) = i
Proof step 25:
¬(~128 ≤ 256 + j ∧ 256 + j ≤ 127), j < ~1, j < 0, ~256 < j, ~256 ≤ j, j < ~128 ⊦ b2i(i2b(256 + j)) = 256 + j

Rule argument

name: num-ibbi rotate: F subst: [i] → [256 + j]

Additional information

Used simplifier rules: ⊦ i + j = j + i; Used terms: 256 + j