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Proof step 24 from proof bib-on-bits (previous step)

⊦ b2i(i2b(bits2int(lastn(8, int2bits(i))))) = bits2int(lastn(8, fillsgn(8, int2bits(i)))), i ∈byte

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ n ≤ # bits → fillsgn(n, bits) = bits subst: [bits, n] → [int2bits(i), 8] rotate: F spec: bitopsaux inst: name: fillsgn-longer

Additional information

Used terms: int2bits(i), 8