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Proof step 40 from proof bib-on-bits (previous step)

8 ≤ # int2bits(i) ⊦ b2i(i2b(bits2int(lastn(8, int2bits(i))))) = bits2int(lastn(8, int2bits(i))), i ∈byte

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 41:
⊦ i ∈byte ↔ ~128 ≤ i ∧ i ≤ 127
Proof step 42:
8 ≤ # int2bits(i) ⊦ b2i(i2b(bits2int(lastn(8, int2bits(i))))) = bits2int(lastn(8, int2bits(i))), ~128 ≤ i ∧ i ≤ 127

Rule argument

name: inbyte rotate: F subst: [i] → [i]

Additional information

Used terms: i