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Proof step 4 from proof bint-is-cast-01 (previous step)

⊦ bi2i(i2bi(i)) = bi2i(i2bi(cast(32, i))), i2bi(i) = i2bi(cast(32, i))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ bi2i(i2bi(i)) = cast(32, i)
Proof step 6:
⊦ bi2i(i2bi(i)) = cast(32, cast(32, i)), i2bi(i) = i2bi(cast(32, i))

Rule argument

name: bint-is-cast rotate: F subst: [i] → [cast(32, i)]

Additional information

Used terms: cast(32, i)