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Proof step 6 from proof bint-is-cast-01 (previous step)

⊦ bi2i(i2bi(i)) = cast(32, cast(32, i)), i2bi(i) = i2bi(cast(32, i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
⊦ i2bi(i) = i2bi(cast(32, i)), bi2i(i2bi(i)) = cast(32, i)

Rule argument

Additional information

Used simplifier rules: ⊦ 0 < i → cast(i, cast(i, j)) = cast(i, j);