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Proof step 10 from proof bint-is-cast (previous step)

# int2bits(i) ≤ 32 ⊦ bi2i(i2bi(bits2int(lastn(32, int2bits(i))))) = cast(32, i), i ∈bint

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ i ∈bint ↔ ~2147483648 ≤ i ∧ i ≤ 2147483647
Proof step 12:
# int2bits(i) ≤ 32 ⊦ bi2i(i2bi(bits2int(lastn(32, int2bits(i))))) = cast(32, i), ~2147483648 ≤ i ∧ i ≤ 2147483647

Rule argument

name: inbint rotate: F subst: [i] → [i]

Additional information

Used terms: i