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Proof step 9 from proof bint-is-cast (previous step)

¬ 32 < # int2bits(i) ⊦ bi2i(i2bi(bits2int(lastn(32, int2bits(i))))) = cast(32, i), i ∈bint

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ m < n ↔ n ≤ m;