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Proof step 19 from proof bint-is-cast (previous step)

32 < # int2bits(i) ⊦ bi2i(i2bi(cast(32, i))) = cast(32, i), i ∈bint

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 20:
⊦ i ∈bint → bi2i(i2bi(i)) = i
Proof step 21:
¬ cast(32, i) ∈bint, 32 < # int2bits(i) ⊦ bi2i(i2bi(cast(32, i))) = cast(32, i), i ∈bint

Rule argument

name: biibi-in rotate: F subst: [i] → [cast(32, i)]

Additional information

Used terms: cast(32, i)