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Proof step 21 from proof bint-is-cast (previous step)

¬ cast(32, i) ∈bint, 32 < # int2bits(i) ⊦ bi2i(i2bi(cast(32, i))) = cast(32, i), i ∈bint

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
32 < # int2bits(i) ⊦ bi2i(i2bi(cast(32, i))) = cast(32, i), cast(32, i) ∈bint, i ∈bint

Rule argument

Additional information