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Proof step 4 from proof byte-equal (previous step)

i2b(b2i(byi)) = byi, b2i(byi) = b2i(byj) ⊦ byi = byj

User applied rule insert lemma

And obtained the following new goals

Proof step 5:
⊦ i2b(b2i(by)) = by
Proof step 6:
i2b(b2i(byj)) = byj, i2b(b2i(byi)) = byi, b2i(byi) = b2i(byj) ⊦ byi = byj

Rule argument

name: ibi subst: [by] → [byj]

Additional information

Used terms: byj